Error handling in C++?

Hi experts!





I'm learning C++. I wish to write a C++ program with exception handling.





Please give a simple program for divisor by zero using C++.


And detail syntax for defining exception.

Error handling in C++?
Unlike Java, C++ does not have a standard exception for divide-by-zero so you have to build your own. Many, arguably all, exceptions in c++ should be derived from the standard exceptions in, oddly enough, the stdexcept header file. Since this is a runtime error this example derives from std::runtime_error.





This should help you get started but it is obviously not a complete treatment of the topic of exceptions. You should read more on your own.





#include %26lt;iostream%26gt;


#include %26lt;exception%26gt;


#include %26lt;stdexcept%26gt;





using namespace std;





class DivideByZeroException : public runtime_error


{


public:





DivideByZeroException() : runtime_error("attempt to divide by zero" ) {}


};








int main()


{


int num;


int dem;


int res;





cout %26lt;%26lt; "Enter numerator: ";


cin %26gt;%26gt; num;


cout %26lt;%26lt; "Enter denominator: ";


cin %26gt;%26gt; dem;





try


{


if (dem == 0)


{


throw DivideByZeroException();


}





res = num / dem;





cout %26lt;%26lt; "Result = " %26lt;%26lt; res %26lt;%26lt; endl;


}





catch (DivideByZeroException %26amp;e)


{


cout %26lt;%26lt; "Exception: " %26lt;%26lt; e.what() %26lt;%26lt; endl;


}





return(0);


}
Reply:#include%26lt;stdio.h%26gt;


#include%26lt;conio.h%26gt;


#include%26lt;iostream.h%26gt;


void main()


{


int a,b,c;


cin%26gt;%26gt;a;


cin%26gt;%26gt;b;


try


{


if(b==0)


throw(1);


}


catch(int)


{


cout%26lt;%26lt;"divide error";


}


getch();


}
Reply:use try and catch block. keep the code that causes exception in try block n the code for handling error in catch block.





try{


int i = 5/0;


}


catch(Exception e){ // well this is java code but still c++ code is similar


// handle


}

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